Physics, asked by akshayshenoy7560, 1 year ago

Calculate the force required to impart a velocity of 30m/s in 10 sec ,if the mass of the body is 1.5 ton

Answers

Answered by PSN03
46

Answer:

4500 N

Explanation:

We know that force can also be called as the rate of change of momentum and hence we can freely apply the formulas given to calculate force:

  • F=ma
  • F*t=Pf-Pi
  • P=mv

where

F=force acting on the body

m=mass of the body

a=acceleration of the body

t=time for which the force is imparted

Pf=final momentum of the body

Pi=initial momentum of the body

We are given that:

u=0 m/s

v=30 m/s

t=10 s

m=1.5 ton=1.5*1000 kg

=1500 kg

We can write the formula to be used as:

F*t=m*v-m*u

Since all the required values are with us we can directly plug in the values to get force

F*10=1500*30-1500*0

F*10=45000

F=4500 N

Therefore the force required is 4500 N

Hope this helps

Answered by BrainlyConqueror0901
47

{\bold{\underline{\underline{Answer:}}}}

{\bold{\therefore Force\:applied=4500\:N}}

{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

• In the given question information given about a body of mass 1.5 ton and its final velocity and time is given.

• We have to Calculate the force required to impart a velocity of 30m/s in 10 sec.

 \underline \bold{Given :} \\  \implies Mass \: of \: body = 1.5 \: ton \\ \\  \implies Initial \: velocity(u) = 0 \\   \\ \implies Final \: velocity  (v)= 30 \: ms \\  \\  \implies Time = 10 \: sec \\  \\  \underline \bold{To \: Find  : }  \\  \implies  Force \: required = ?

• According to given question :

 \bold{mass = 1.5 \: ton = 1500 \: kg} \\  \\ \bold{ By \: formula \: of \: force : } \\  \implies F = ma  -  -  -  -  - (1)\\  \\  \bold{F = Force} \\  \bold{m = Mass} \\ \bold{ a  = Acceleration} \\  \\  \bold{by \: first \: equation \: of \: motion : }\\ \implies v = u + at \\ \\  \implies v - u = at \\  \\  \implies  \bold{a =  \frac{v - u}{t}  }-  -  -  -  - (2) \\  \\  \bold{Putting \: value \: of \: a \: in \: (1)} \\ \implies F =  m \times  \frac{v - u}{t}  \\  \\  \implies F = 1500 \times  \frac{3 \cancel{0 }- 0}{ \cancel{10}}  \\  \\  \implies F= 1500 \times 3 \\   \\  \bold {\implies F= 4500 \: N} \\  \\     \bold{\therefore Force \: applied \: to \: move \: the \: body }  \\  \:  \:  \: \bold {at \: 30 \: ms \: is \: 4500 \: N}

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