calculate the force required to imported velocity of 30 m/s in 10 seconds the mass of car is 1500 kg?
Answers
Answered by
54
we have
,mass=1500kg
final velocity,v=30m/s,
time=10s
so,initial velocity,u=0m/s
by the equation of motion,
v=u+at
30=0+a*10
30/10=a
a=3m/s²
we know that,
force = mass*acceleration
f=m*a
f=1500kg*3m/s²
f=4500N
hence force requared to impart to a car is 4500N
,mass=1500kg
final velocity,v=30m/s,
time=10s
so,initial velocity,u=0m/s
by the equation of motion,
v=u+at
30=0+a*10
30/10=a
a=3m/s²
we know that,
force = mass*acceleration
f=m*a
f=1500kg*3m/s²
f=4500N
hence force requared to impart to a car is 4500N
Answered by
22
Given:
mass(m)=1500 kg
final velocity(v)=30 m/s
time(t)=10 s
initial velocity(u)=0 m/s
by Newton's first equation of motion,i.e.
v=u+at
30=0+a×10
30/10=a
∴a=3 m/s²
∵ f=m×a
∴f=1500 kg× 3 m/s²
∴f=4500 N
mass(m)=1500 kg
final velocity(v)=30 m/s
time(t)=10 s
initial velocity(u)=0 m/s
by Newton's first equation of motion,i.e.
v=u+at
30=0+a×10
30/10=a
∴a=3 m/s²
∵ f=m×a
∴f=1500 kg× 3 m/s²
∴f=4500 N
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