Calculate the force required to push a 20kg wooden box over a floor at constant speed (coefficient of friction =0.25)
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we know that force(f) = ma
= 20×9.8=196 newton
due to friction the force required more i.e., 196÷0.25= 784 newton
= 20×9.8=196 newton
due to friction the force required more i.e., 196÷0.25= 784 newton
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