Question

calculate the force required to stop a car of mass 1000kg and a loaded truck of mass 10000kg in 2sec, if they are moving with a same velocity of 5m/s.

Answer 1

to stop car of mass 1000 kg
v=u+at
-u/t = 5/2

ma = 1000*5/2
= 2500 N

for 10000 kg
ma = 25000N

both these forces in the opposite direction of their movement.
hope this helps.

Answer 2

Answer:

The force required to stop the car and the loaded truck is 2500N and 25000N respectively.

Explanation:

The required force is calculated as,

$F=\frac{mv}{t}$       (1)

Where,

F=force required

m=mass of the body

v=velocity with which the body is moving

t=time during which the body is moving

From the question we have,

The mass of the car(m)=1000kg

The mass of the loaded truck(M)=10000kg

Time(t)=2 seconds

For the car

We get the following results by plugging the relevant values into equation (1):

$F=\frac{1000\times 5}{2}$

$F=2500N$    (2)

For the loaded truck

We get the following results by plugging the relevant values into equation (1):

$F=\frac{10000\times 5}{2}$

$F=25000N$   (3)

Hence, the force required to stop the car and the loaded truck is 2500N and 25000N respectively.

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