Question

calculate the forcebetweentwo balls each havinga charge of 12c and are.8 cm Apart​

Answer 1

Answer:

Correct option is

D

13J

Given two charges q

1

=12μC, q

2

=8μC are at distance 'd

1

'=10cm

We have to find the work done in bringing them d

2

=4cm closer.

For this, we find the charge in the potential energy of the system and then take the difference.

Now d

1

=10cm=10×10

−2

=10

−1

m

d

2

=4cm=4×10

−2

m

So, potential (V

1

) when q

1

and q

2

are distance d

1

apart,

V

1

=

4πε

0

1

d

1

q

1

q

2

Potential (V

2

) when q

1

and q

2

are distance d

2

apart,

V

2

=

4πε

0

1

d

2

q

1

q

2

Work done =V

2

−V

1

=

4πε

0

1

q

1

q

2

(

d

2

1

−

d

1

1

)

=9×10

9

×12×8×10

−12

(

4×10

−2

1

−

10×10

−2

1

)

=864×10

−3

[

40×10

−2

6×10

2

]

=129.6×10

1

=12.96≈13Joules

Explanation:

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