Question

Calculate the formula mass of the (AL2O3) aluminium oxide

Answer 1

a. 101.961 amu's 
b. 1.69 x 10^-22 
c. 4.0015, 408 divided by molar mass 
d. 3.437x10^18, moles times Avagadro's #, 6.022x10^23 
e.2, because one mol of Al2O3 breaks down into 2 Al 
f. 2 mol Al x 29.98g/mol = 60g

Answer 2

$\bold{FORMULA \: MASS}$

It is the sum of atomic weight of all the elements constituting that conpound.

$\bold{FOR \: Al_2O_3}$

Bauxite is an ore of aluminium used in the extraction of pure alumina from it. Since, its a metallic oxide its basic in nature.

Bauxite have two atoms of aluminium and three atoms of oxygen.

Atomic weight of aluminium = 27 g

Atomic weight of oxygen = 16g

$\mathsf{ 2 \times Aluminium + 3 \times Oxygen}$

$\mathsf{ 2 \times Al + 3 \ times O}$

$\mathsf{2 \times (27) + 3 \times (16)}$

$\mathsf{2 \times 27 + 3 \times 16}$

= $\mathsf{54 + 48}$

= $\huge \boxed{102 \: g}}$