Question

Calculate the formula of :- i) Calcium hydroxide, ii) Slaked lime, iii) Copper nitrate, iv) Sodium chloride, v) Nitric acid, vi) Hydrochloric acid, vii) Sulphuric acid.

Answer 1

$\huge \boxed {ANSWER}$

◼$\bold{Calcium \: oxide}$

▶Calcium is a metal which lies in group 2 and period 4.

ELECTRONIC CONFIGURATION =2,8,8,2

VALENCE ELECTRONS = +2.

▶ When Hydroxl ${OH^{-1}$reacts with calcium loses its electron. Since, the valence of hydroxl ${OH^{-1}$ is -1 so, two hydroxl ions will be needed.

▶$OH^{-1} \longrightarrow Ca^{+2} \longleftarrow OH^{-1}$

▶$[{OH}^{-1}][{Ca}^{+2}][{OH}^{-1}]$

▶$Ca(OH)_2$

◼$\bold{Slaked \: lime }$

▶Calcium hydroxide is also known as slaked lime.

◼$\bold{COPPER \: NITRATE }$

▶Copper is metal which lies in group 11 and period 4.

▶Where copper has variable valencey +1 and +2.But when it reacts with nitrate radical it firms it with its di valency .

▶$Cu^{+2} \longrightarrow (NO_3)^{-1}]$

▶$[Cu^{+2}][(NO_3)^{-1}]$

▶$Cu(NO_3)_2$

◼$\bold{SODIUM \: CHLORIDE }$

▶Sodium is a metal which lies in group 1 and period 1.

ELECTRONIC CONFIGURATION =2,8,1.

VALENCY = -1.

▶When sodium reacts with chloride ion it loses its one electron and chloride ion gains one electron .

▶$Na^{+1} \longrightarrow (Cl)^{-1}]$

▶$[Na^{+1}][(Cl)^{-1}]$

▶$NaCl$

◼$\bold{NITRIC \: ACID }$

The Hydrogen ion shares its one electron with the nitrate radical to form nitric acid.

▶$H^{+1} \longrightarrow (NO_3)^{-1}]$

▶$[H^{+1}][(NO_3)^{-1}]$

▶$HNO_3$

◼$\bold{HYDROCHLORIC \: ACID }$

▶The hydrogen ion reacts with chloride ion reform hydrochloric acid by sharing its one electron with chloride ion.

▶$H^{+1} \longrightarrow (Cl)^{-1}]$

▶$[H^{+1}][(Cl)^{-1}]$

▶$HCl$

◼$\bold{SULPHIRIC\: ACID }$

▶The hydrogen ion reacts with sulphate ion to form sulphuric acid. In this hydrogen ion shares its one with sulphate ion .Since, the valency of sulphate radical is -2 two hydrogen ion reacts in the formation of sulphate radical.

▶$H^{+1} \longrightarrow (SO_4)^{-2}$

▶$[H^{+1}][(SO_4)^{-2}][H^{+1}]$

▶$H_2SO_4$