Calculate the formula unit mass of CuSo4.5H2o.(Atomic mass of Cu=2,S=32, O=16,H=1).
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Formula-unit mass of CuSO4 • 5H2O = 63.5 + 32 + (4 × 16) + 5{(2 × 1) + 16} u
= 63.5 + 32 + 64 + 90 u
= 249.5 u
MARK IT AS BRAINLIST ANSWER
= 63.5 + 32 + 64 + 90 u
= 249.5 u
MARK IT AS BRAINLIST ANSWER
Anya50:
Thank you
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atomic mass of H = 1 g
atomic mass of O = 16 g
atomic mass of Cu =63.5 g
atomic mass of S = 32 g
now ,
molar mass of CuSO4.5H2O = atomic mass of Cu + atom mass of S + 4× atomic mass of O +5× {2 × atomic mass of H + atomic mass of O }
= 63.5 + 32 + 4× 16 +5 (2 + 16) g
=63.5 +32 + 64 + 90 g
= 249.5 g
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