Question

Calculate the four quantum values of 3p4 for 4th electron.

Answer 1

Principal quantum number(n) = 3

Azimuthal quantum number(l) = 1

Magnetic quantum number(m) = -1, 0 or +1

Spin quantum number(s) = -1/2

Answer 2

Given: Given orbital is $3p^4$.

To find: We have to find the value of the four quantum numbers.

Solution:

n is called the principal quantum number. The value of n for $3p^4$ is 3.

l is called the azimuthal quantum number and for p orbital, its value is 1.

The given orbital has four electrons so, the spin quantum number for the fourth electron is -1/2 as it is present in an opposite spin.

m is called the magnetic quantum number and its value is +1,0,-1.

The value of the four quantum numbers are-

n=3

l=1

s=-1/2

m=+1,0,-1