Question

Calculate the free energy change per mole for the following reactions. (1) CaCO,(s) + CaO(s) + CO,(g) 298K V AH = 1179 kJ, AS = 160,43K-

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Answer 1

Answer:

The Gibbs free energy change of the reaction is -130.1 kJ and the reaction is spontaneous in nature.

Explanation:

For the given chemical equation:

CaCO3 + CaO+CO(9)

To calculate the Gibbs free energy of the reaction, we use the equation:

AGAH-TAS

where,

AH = enthalpy change = +177.9 kJ = 177900 J (Conversion factor: 1 kJ = 1000 J)

T = Temperature = 298 K

AS = entropy of the reaction = -160.4 J/K

Putting values in above equation, we get:

AG 177900J (298K × (-160.4J/K))

AG = -130100.8J = -130.1kJ

For a reaction to be spontaneous, the Gibbs free energy of the reaction must be negative.

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