Calculate the free energy change per mole for the following reactions.
(i) CaCO3
(s) + CaO(s) + CO2
(g) 298K ij
∆H = 117.9 kJ, ∆S = 160.4JK–1
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Answer:
Correct option is B)
CaCO3(s)⟶CaO(s)+CO2(g) Δng=1−0=1
T=977℃=977+273=1250K
ΔE=ΔH−ΔngRT
(=174×(103)−1(8.314)×(1250)) J
=163.6 kJ
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