Question

Calculate the freezing point of 0.01 molal solution of glucose in water

Answer 1

may it will be helpful to you

Answer 2

The Freezing point of glucose in water is -0.0186k.

Given:-

Molality (m) = 0.01 molal

To Find:-

Freezing point of glucose in water.

Solution:-

We can easily solve the Freezing point of glucose in water by using the following procedure.

As,

Molality (m) = 0.01 molal

Freezing constant (kf) = 1.86

According to the formula,

$d(tf) = kf \times m$

$d(tf) = 1.86 \times 0.01$

$d(tf) = 0.0186$

$tf - tfo = 0.0186$

$0 - tfo = 0.0186$

$tfo = - 0.0186k$

Hence, the Freezing point of glucose in water is -0.0186k.

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