Calculate the freezing point of a 1molar solution
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Answer:
Explanation:
1ml. Solution is equivalent to 1.06 gram.
1000ml. Solution is equivalent to 1060 gm mass.
1molar KBr solution means 1000 ml solution has 1mole of KBr dissolved in it.
119 gm KBr is in 1060–119 gm water i,e 941 gm water.
1000 gm water means 1.062 moles of KBr.
Molality of the solution is 1.062.
Van’t Hoff factor of KBr =2.
Delta Tb = 2 × 1.062× 0.52 K=1.087 K .
Boiling point of solution =373.15+ 1.087K = 374.137 K.
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Answer:freezing. Point. = - 1.86
Explanation:
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