Question

Calculate the freezing point of an aqueous solution of a nonelectrolyte exhibiting an

Answer 1

π=2 atm

S=0.0821 litre atm k−1mol−1

T=300K

Also πV=nST

∴ Molarity =nV=πST

⇒20.0821×300

⇒ 0.0812 mole litre−1

For dilute solutions molarity =molality=0.0812

ΔT=Kf× molality=1.86×0.0812

⇒0.151

Freezing point =T0−ΔT

⇒0−0.151

⇒−0.151∘C

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