Calculate the frequency and energy of a photon whose wavelength is having 6200 A⁰
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Frequency v=cλ
Substituting c=3×108ms−1,λ=6000Å=6000×10−10m, we get
v=3×108ms−16000×10−10m=5×104s−1
(ii) Energy of the photon E = hv
Substituting h=6.625×10−34Js,v=5×1014s−1, we get
E=6.625×10−34Js×5×1014s−1=3.3125×10−19Jwer:
Explanation:
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