Question

calculate the frequency and the wavelength of the radiation in nanometres emitted when an electron in the hydrogen atom jumps from third Orbit to the ground state.in which region of the electromagnetic spectrum will this lie?

Answer 1

hey there is answer !!

Part : I

To find wavelength :





where nf = 1 , n2= 3  and R= 1.097 x107m-1
1/(λ) = 1.1 x 107 (1/12 - 1/32)  
1/(λ) = 1.1 x 107 (1-1/9)
1/(λ) = 1.1 x 107 (8/9)

(λ)  = (9)/(8 x 1.1 x 107)
(λ) = 1.02 x 10-7 m

To find frequency  :


v = c/meu


Frequency = (3.8 x 108 m/s)/(1.02 x10-7 m)
 =  3.72 x 10 -15 m

Answer 2

Hope it helps !

Thank u !!