Question

Calculate the frequency and wave number of a photon emitted during the electron transition in hydrogen from n=4 to n=1

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Answer 1

Answer:

odyy0d0sy

Explanation:

• d0ogxpyzpgzpy,dm 5a9ts9taotst9aptatoaptstpsotat9s9taotstosotatoatoalGypaltstpsypatpatpsypspyspysp0ey06s0yst0sy0stpspyspysypssyp0ysy0sy0suspsyosttsztt0s0syotsst9s0tspysptz

st00ys0ys0ys0yspyzyspystpaypypdtospyspyspysypsypedpyspyspyssuy0st9sots9tshpdypsys0ptsyps0syy0sys0pys0ys0ysduy0s0ys0ts0yst0s0yspysy0spyspyspyzpspyzs0ypsy0sypyst0s0ys0yspysysppyspyspysypspysypssyppyssypypssupys9tay0s0ys0ysys0ys0ys0ts0sy0t0s0ta0ts0st0tsst0ap

Answer 2

Answer:

10.2822×10^-5

Explanation:

(v )=109677(1÷n1^2-1÷n2^2)cm/s

=109677(1÷4^2-1÷1^2)

=109677(1÷16-1)

=109677(15÷16)

=102822.18cm/s

wavenumber=10.2822×10^-5