Question

calculate the frequency of an electron in the first bohr Orbit in hydrogen atom​

Answer 1

frequency of an electron in the first Bohr orbit in hydrogen atom is 0.657× 10^18 s^-1

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Answer 2

The frequency of an electron in the first bohr Orbit in hydrogen atom​ is $3.291\times 10^{15}s^{-1}$

Explanation:

$\frac{1}{\lambda}=R_H\times \frac{Z^2}{n^2}$

where,

$\lamba$ = wavelength

$R_H$ = Rydberg constant

n = number of orbit

Z = atomic number

We have:

$n=1$

$R_H=1.097\times 10^7 m^{-1}$

$\frac{1}{\lambda}=1.097\times 10^7 m^{-1}\times \frac{1^2}{1^2}$

$\frac{1}{\lambda}=1.097\times 10^7 m^{-1}$

$\lambda=0.9115\times 10^{-7} m$

$\lambda=\frac{c}{\nu}$

where,

$\lambda$ = wavelength of the light  

c = speed of light = $3\times 10^8m/s$

$\nu$ = frequency of light

$0.9115\times 10^{-7}=\frac{3\times 10^8m/s}{\nu}$

${\nu}=3.291\times 10^{15}s^{-1}$

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