Question

Calculate the frequency of particle wave, when the kinetic energy of a sub atomic particle is 3.79?10^-27 J.

Answer 1

Final Answer : 1.14 * 10^(7) Hz

Steps :
1) We know, For any matter,
By Debroglie Relation,
$\lambda \: = \frac{h}{p}$
where Lambda is wavelength of matter.
h = Plancks Constant
p = momentum of matter.
And,
Velocity = frequency * Wavelength
v = f * lambda

2) Now,
Kinetic Energy of matter having mass m, velocity v.
KE = 1/2 mv^2
=> KE = 1/2 *(p) * v
$= > \frac{1}{2} \times \frac{h}{ \lambda} \times (f \times \lambda) \\ = > \frac{hf}{2}$

Then, KE = hf/2
=>
$3.79 \times {10}^{ - 27} = \frac{6.626 \times {10}^{ - 34} \times f}{2} \\ \\ = > f = \frac{2 \times 3.79 \times {10}^{7} }{6.626} \\ = > f = 1.14 \times {10}^{7} \: hertz$


Hence, Frequency of sub-atimic particle is
1.14 * 10^(7) He

Answer 2

Answer:

frequency of particle wave = 1.143×10^7

Explanation:

We have given kinetic energy from this information we may find velocity and put this in equation of de-broglie equation where we got the value of lambda and after that take relation of lambda and frequency and we get frequency from here..m.m

I hope it may help you....

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