Question

Calculate the frequency of visible light having wavelength 3000A travelling in vacuum.
the reason​

Answer 1

Answer:

v=nu.lambda

nu =v/lambda

3×10^8/3×10^3

so frequency=10^5

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Answer 2

Answer:

The frequency of the visible light is $10^{15}\ Hz$.

Step-by-step explanation:

Given that,

The wavelength of the visible light, $\lambda=3000\ A=3000\times 10^{-10}\ m=3\times 10^{-7}\ m$

The velocity of the electromagnetic wave is given by the formula as :

$c=f\lambda\\\\f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8\ m/s}{3\times 10^{-7}\ m}\\\\f=10^{15}\ Hz$

So, the frequency of the visible light is $10^{15}\ Hz$. Hence, this is the required solution.