Calculate the fundamental frequency of the wave in an organ pipe of length 4cm which is closed at one end. The temperature of the organ pipe is 35
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Given:
Organ pipe of length, l = 4cm
Temperature of the pipe = 35°C
To Find:
The fundamental frequency of the wave in the organ pipe.
Solution:
Fundamental frequency of the organ pipe is given by,
- f = V/4L
- V is the velocity of sound.
Velocity of sound varies with room temperature as:
- V = Vo√T/273 ,
- T is in Kelvin, Vo is velocity at room temperature.
- Vo = 346m/s
- V = 346 x √273+35/273 = 346 x √308/273 = 367.5 m/s
Therefore fundamental frequency ,
- f = 367.5/4 x 0.04 = 2296.9 Hz = 2.296KHz
The fundamental frequency of the wave in an organ pipe of length 4cm which is closed at one end is 2.296KHz.
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