Question

Calculate the gradient of the curve at the point where x = 1 ? y = x^3 +7

Answer 1

$here \\ x = 1 \\ y = {x}^{3} + 7 \\ we \: put \: the \: value \: of \: x \: in \: y = {x}^{3} + 7 \\ y = {1}^{3} + 7 \\ y = 1 + 7 \\ y = 8$

The value of. y = 8