Question

calculate the gram of atoms present in 8gram of oxygen​

Answer 1

Explanation:

8g oxygen = 41 mole of oxygen =26. 022×1023 atoms =3.

Answer 2

Answer:

A molecule of oxygen consists of 2 atoms of O2.

So the molar mass of O2 molecule is

16 x 2 = 32g

So, 32g of O2 will have 6.022 X 10^23 molecules of O2

Therefore

1g of O2 will have (6.022 X 10^23)/32 molecules of O2

So finally, 8g of of O2 will have

(6.022 X 10^23 x 8)/32 molecules of O2

The above eqn will be 1.506 X 10^23 molecules of O2

Explanation:

please mark as brain list