Question

Calculate the gravitational force between a 40kg sphere and a 100kg sphere placed at a distance of 4m. (Take G=6.7X10-11 Nm2/Kg2)

Answer 1

Given :

Two spheres of masses 40kg and 100kg respectively are placed at a distance of 4m.

To Find :

Gravitational force acts between them.

Solution :

❒ The magnitude of gravitational force between two point masses is directly proportional to the product of masses and inversely proportional to the square of distance between them.

This is known as Newton's law of gravitation.

Formula :-

$\dag\:\underline{\boxed{\bf{\purple{F=G\:\dfrac{m_1m_2}{r^2}}}}}$

• G = 6.67 × 10‾¹¹ N m² / kg²

By substituting the given values;

$\sf:\implies\:F=6.67\times10^{-11}\times\dfrac{40\times100}{4^2}$

$\sf:\implies\:F=6.67\times10^{-11}\times\dfrac{4\times 10^3}{16}$

$\sf:\implies\:F=\dfrac{6.67\times 10^{-11}\times 10^3}{4}$

$:\implies\:\underline{\boxed{\bf{\red{F=1.66\times 10^{-8}\:N}}}}$

Answer 2

Given :

Two spheres of masses 40kg and 100kg respectively are placed at a distance of 4m.

To Find :

Gravitational force acts between them.

Solution :

❒ The magnitude of gravitational force between two point masses is directly proportional to the product of masses and inversely proportional to the square of distance between them.

This is known as Newton's law of gravitation.