Calculate the gravitational force between two objects when distance between them is doubled?
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Explanation:
Case (ii) : Distance between the objects is doubled i.e r′=2r. ∴ F′=(2r)2Gm1m2 ⟹F′=4F. Thus gravitational force gets reduced by 4 times.
Distance between the objects is tripled i.e r′=3r. ∴ F′=(3r)2Gm1m2 ⟹F′=9F. ...
Case (iii) : Mass of both the objects are doubled i.e m1′=2m1 and m2′=2m2. ∴ F′=r2G(2m1)(2m2) ⟹F′=4F.
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1.Case (ii) : Distance between the objects is doubled i.e r′=2r. ∴ F′=(2r)2Gm1m2 ⟹F′=4F. Thus gravitational force gets reduced by 4 times.
2.Distance between the objects is tripled i.e r′=3r. ∴ F′=(3r)2Gm1m2 ⟹F′=9F.
3.Case (iii) : Mass of both the objects are doubled i.e m1′=2m1 and m2′=2m2. ∴ F′=r2G(2m1)(2m2) ⟹F′=4F.
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