Question

Calculate the gravitational force by which a stone of mass 1 kg placed on the surface of the Earth is attracted towards its centre. Given, mass of the Earth=6*10^kg and radius of the Earth=6400 km.​

Answer 1

Answer:

Here, `m_(1)=1kg, m_(2)=6xx10^(24)kg`

`d=6400 km =6.4xx10^(6)m, F = ?`

`F = (Gm_(1)m_(2))/(d^(2)) =(6.67 xx 10^(-11)xx1xx6 xx 10^(24))/((6.4 xx10^(6))^(2)) =9.8N`

Answer 2

Mass of stone=m=1kg

mass of earth =M= 6× 10²⁴

radius of earth = 6400km = 6400000m=6.4×10⁶m

We know gravitation force F=GMm/r²=6.67×10‐¹¹×6×10²⁴×1/(6.4×10⁶)²=9.8N 

Where M = mass of the earth, m = mass of the object and R = radius of earth

Hence the gravitational force is 9.8N