Question

Calculate the gravitational force of attraction between the Earth and a 70kg man if he is standing at a sea level, a distance of 6.38 x 106 m from the earth’s center.(Mass of earth 6×1024 kg, G= 6.7×10-11 Nm2 kg-2 )

Answer 1

Given that,

Mass of man, m = 70 kg

Mass of Earth, $M=6\times 10^{24}\ kg$

Distance from Earth's surface, $d=6.38\times 10^6\ m$

To find,

The gravitational force of attraction between the Earth and the man.

Solution,

The gravitational force between Earth and man is given by formula as follows :

$F=G\dfrac{mM}{d^2}\\\\F=6.7\times 10^{-11}\times \dfrac{70\times 6\times 10^{24}}{(6.38 \times 10^6)^2}\\\\F=691.32\ N$

So, the gravitational force between Earth and man is 691.32 N.

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Gravitational force

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