Calculate the ground state and Lande splitting factor of HO3+ ion in the configuration 4f10.
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Because Iron is not the representative metal element, which means the electron configuration of Fe is not the same as the general order but in the order of principal quantum number:
Because Iron is not the representative metal element, which means the electron configuration of Fe is not the same as the general order but in the order of principal quantum number:
Because Iron is not the representative metal element, which means the electron configuration of Fe is not the same as the general order but in the order of principal quantum number: Fe = 1s2 2s2 2p6 3s2 3p6 3d6 4s2
Because Iron is not the representative metal element, which means the electron configuration of Fe is not the same as the general order but in the order of principal quantum number: Fe = 1s2 2s2 2p6 3s2 3p6 3d6 4s2
Because Iron is not the representative metal element, which means the electron configuration of Fe is not the same as the general order but in the order of principal quantum number: Fe = 1s2 2s2 2p6 3s2 3p6 3d6 4s2 In this case, the Fe atom have to loss the 4s2 electrons first; because the sublevel d and f have two stable state: full of electrons and half of electrons (there must be one electron in each orbital, and d has 5 orbitals), 3d6 has to lose one electron to form 3d5.
Because Iron is not the representative metal element, which means the electron configuration of Fe is not the same as the general order but in the order of principal quantum number: Fe = 1s2 2s2 2p6 3s2 3p6 3d6 4s2 In this case, the Fe atom have to loss the 4s2 electrons first; because the sublevel d and f have two stable state: full of electrons and half of electrons (there must be one electron in each orbital, and d has 5 orbitals), 3d6 has to lose one electron to form 3d5.
Because Iron is not the representative metal element, which means the electron configuration of Fe is not the same as the general order but in the order of principal quantum number: Fe = 1s2 2s2 2p6 3s2 3p6 3d6 4s2 In this case, the Fe atom have to loss the 4s2 electrons first; because the sublevel d and f have two stable state: full of electrons and half of electrons (there must be one electron in each orbital, and d has 5 orbitals), 3d6 has to lose one electron to form 3d5. Fe3+ = 1s2 2s2 2p6 3s2 3p6 3d5
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