calculate the h3po4 concentration prepared by dissolving 0.1 mol of na3po4 In sufficient water to make 1l solution
Answers
11th
Chemistry
Equilibrium
Ionization of Acids and Bases
Calculate the OH^- concentr...
CHEMISTRY
Calculate the OH
−
concentration and the H
3
PO
4
concentration of a solution prepared by dissolving 0.1 mol of Na
3
PO
4
in sufficient water to make 1L of solution.
K
1
=7.1×10
−3
, K
2
=6.3×10
−8
; K
3
=4.5×10
−13
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ANSWER
Na
3
PO
4
+H
2
O⟶Na
2
HPO
4
+NaOH
K=
K
3
K
w
=0.0222
Na
2
HPO
4
+H
2
O⟶NaH
2
PO
4
+NaOH
K=
K
2
K
w
=1.58×10
−7
NaH
2
PO
4
+H
2
O⟶H
3
PO
4
+NaOH
K=
K
3
K
w
=1.4×10
−12
Since equilibrium constant of 2nd and 3rd reaction is very less, [OH
−
] will mainly come from 1st reaction.
Na
3
PO
4
+H
2
O⟶Na
2
HPO
4
+NaOH
0.1
0.1−x x x
0.1−x
x
2
=0.0222 ⇒ 45x
2
+x−0.1=0
x=3.73×10
−2
[OH
−
]=x=3.73×10
−2
M
Na
2
HPO
4
+NaOH⟶NaH
2
PO
4
+NaOH
x
x−y y y+x
x−y≃x
y+x≃x
1.58×10
−7
=
(x−y)
(x+y)
y=y
NaH
2
PO
4
+H
2
O⟶H
3
PO
4
+NaOH
y
y−z z z+x
y−z≃y, z+x≃x
1.4×10
−12
=
(y−z)
z(x+z)
=
y
z×x
=
1.58×10
−7
z×3.73×10
2
z=5..93×10
−18
[H
3
PO
4
]=5.93×10
−18
M
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