Calculate the half cell potential at 298K for the reaction , Zn2+ + e- changes into Zn if Zn2+ =2M
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Answer:
According to Nerast Equation-
E
m
n+
/m=E
∘
m
n+
/m−
n
0.0591
log
[m
n+
]
1
E
Zn
2+
/zn=E
zn
2+
/zn−
2
0.0591
log
[zn
2+
]
1
⇒−0.76−
2
0.0591
log
0.1
10
⇒−0.76−
2
0.0591
⇒
2
−1.52−0.0591
⇒
E
Zn
2+
/zn=−0.789volt
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