Question

Calculate the half life of a first order reaction from rate constant 500 sec
sec-1.​

Answer 1

Can't understand the question

Answer 2

Answer:

Half life of the given first order reaction with is $(1.39)(10^{-3})$

Explanation:

The half life of a first order reaction is a stage at which the concentration of the reactants is half the initial concentration.

The half life of a first order reaction is formulated as:

                                 $t_{\frac{1}{2} }$ =  $\frac{ln 2}{k}$

where k is rate constant of the reaction.

Here as the rate constant is given as $500\ sec^{-1}$.

So, the half life of the first order reaction will be given as

                                 $t_{\frac{1}{2} }$ = $\frac{ln2}{500}=(1.39 )(10^{-3})$  seconds.