Question

Calculate the half life of a first order reaction if the rate constant of a reaction is 6.93×10^-4 s^-1

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Answer 1

Answer:

Half life of First order reaction,

T1/2 = 0.693/k

Putiing k = 6.93 X $10^{-4}$

T1/2  = $\frac{0.693}{6.93 X 10^{-4} }$ = 0.1 X $10^{4}$ = 1000 s