Calculate the half life of first order reaction when rate constant is 2 min 1
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Answer:
a = initial concentration at time
a' = concentration at time t
t= 2.303 /k log ( a/a')
a/a'= 2
log 2 = 0.3
t = 2.303*0.3/k
= 0.693/k
Explanation:
half life of first order reaction = 0.693/ k
= 0.693/2
= 0.3465 min-1
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