Question

Calculate the hall voltage when the Electric Field is 5V/m and height of

the semiconductor is 2cm.​

Answer 1

Answer:

Hall voltage ( VH) =electric field applied x height of semiconductor=Exd.VH= 5x0.02=0.1

Answer 2

Answer:

The hall voltage of the semiconductor is 0.1 V

Explanation:

Hall voltage:

The potential difference that results from applying an external magnetic field perpendicular to the current flowing through an electrical conductor.

Hall voltage in semiconductor:

• The resistance's temperature dependency can be used to calculate a semiconductor's band gap.
• The voltage that is opposed to both magnetic field and current is known as the hall voltage.
• When a magnetic field that is perpendicular to the direction of current flow is applied, it manifests.

• In a semiconductor material, charge carriers experience a force that is transverse to the direction of the applied magnetic field and carriers flow when a magnetic field is applied perpendicular to the direction of flow of charge carriers.  
• This effect is known as hall effect.

Given electric field is 5v/m

Height of the semiconductor is 2cm

$V_{h}$=E*d

  = 5 × $\frac{2}{100}$

  = 5 × $\frac{1}{50}$

   = $\frac{1}{10}$

   = 0.1  v

Final answer:

The hall voltage of the semiconductor is 0.1 V

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