Question

Calculate the hardness of 0.05M Alcl3 and 0.04M Mgcl2?

Answer 1

Answer:

CaCl

2

+Na

2

SO

4

⟶CaSO

4

+2NaCl

Millimoles added 0.02 V 0.0004 x V 0 0

Suppose V mL of both are mixed,

∴[Ca

2+

]=

2V

0.02V

and [SO

4

2−

]=

2V

0.0004V

∴[Ca

2+

][SO

4

2−

]=

2V

0.02V

×

2V

0.0004V

=2×10

−6

Thus, [Ca

2+

][SO

4

2−

] in solution <K

sp

So, precipitate will not form.

Answer 2

Answer:

Explanation:

the hardness of 0.05M Alcl3 and 0.04M Mgcl2