Calculate the hardness of 0.05M Alcl3 and 0.04M Mgcl2?
Answers
Answered by
2
Answer:
CaCl
2
+Na
2
SO
4
⟶CaSO
4
+2NaCl
Millimoles added 0.02 V 0.0004 x V 0 0
Suppose V mL of both are mixed,
∴[Ca
2+
]=
2V
0.02V
and [SO
4
2−
]=
2V
0.0004V
∴[Ca
2+
][SO
4
2−
]=
2V
0.02V
×
2V
0.0004V
=2×10
−6
Thus, [Ca
2+
][SO
4
2−
] in solution <K
sp
So, precipitate will not form.
Answered by
0
Answer:
Explanation:
the hardness of 0.05M Alcl3 and 0.04M Mgcl2
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