Question

calculate the hardness of sample water in ppm which contain 0.01gm mgcl2 per liter​

Answer 1

Answer:

10ppm

Explanation:

55.5 g CaCl

2

≡50 g CaCO

3

55.5 mg CaCl

2

≡50×10

−3

g CaCO

3

47.5 g MgCl

2

≡50 g CaCO

3

47.5 mg MgCl

2

≡50×10

−3

g CaCO

3

Total CaCO

3

=(50+50)×10

−3

=10

−2

g/L

Hardness in terms of ppm =

1000

10

−2

×10

6

mL =10 ppm