Question

Calculate the hardness of water sample containing 2.4 mg of calcium chloride in 500 ml of water. (Ans: 4.32 ppm)​

Answer 1

Verified answer ✔️

55.5 g CaCl2 ≡ 50 g CaCO3

55.5 mg CaCl2 = 50×10−3 g CaCO3

47.5 g MgCl2 =50 g CaCO3

47.5 mg MgCl2 =50×10−3 g CaCO3

Total CaCO3 = (50+50)×10−3 = 10−2 g/L

Hardness in terms of ppm =100010−2×106 mL = 10 ppm

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