Math, asked by uniqueboypaul, 11 months ago

calculate the HCF of k, 2k, 3k , 4k ,5k?
a) rational number
b) an irrational numbers
c) A whole number
d). All of above . Tick and explain answer .​

Answers

Answered by crystalch24092
5

Answer:

d) All of above.

Step-by-step explanation:

k = k x 1

2k = k x 2

3k = k x 3

4k = k x 4

5k = k x 5

=> HCF of k, 2k, 3k, 4k and 5k is k .

And k can be a rational number , an irrational number as well as a whole number too...

Answer..

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