Calculate the heat absorbed by 200 g of ice at 0 to change to water at 40 . (Specific latent heat of ice = 336 J/g ; Specific heat capacity of water = 4.2 J/g )
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Answer:
Heat extracted by ice at 0
o
C to melt = Heat given by water to reach 0
o
C from 40
o
C.
ML=mcθ
Where, θ = change in temperature of water
L = Specific Latent heat of ice
c = Specific heat capacity of water
M = Mass of ice required
m = mass of water
M×336=300×4.2×(40−0)
M=
336
300×4.2×40
=150g
∴ Ice required to lower the temperature of water =150g
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