Calculate the heat capacity of a piece of wood if 1500.0 g of the wood absorbs 6.75 x 104 joules of heat, and its temperature changes from 32 degrees C to 57 degrees C.
Answers
Explanation:
A substance's specific heat tells you how much heat much either be added or removed from
1 g
of that substance in order to cause a
1
∘
C
change in temperature.
The equation that establishes a relationship between specific heat, heat added or removed, and change in temperature looks like this
q
=
m
⋅
c
⋅
Δ
T
, where
q
- the amount of heat added / removed
m
- the mass of the sample
c
- the specific heat of the substance
Δ
T
- the change in temperature
In your case, the
1500.0-g
piece of wood is said to absorb a total of
6.75
⋅
10
4
J
of heat. This caused its temperature to increase from
32
∘
C
to
57
∘
C
.
The difference between the final temperature and the initial temperature of the sample will be the value for
Δ
T
.
Δ
T
=
57
∘
C
−
32
∘
C
=
25
∘
C
This means that the specific heat of the wood is equal to
q
=
m
⋅
c
⋅
Δ
T
⇒
c
=
q
m
⋅
Δ
T
Plug in your values to get
c
=
6.75
⋅
10
4
J
1500.0 g
⋅
25
∘
C
=
1.8
J
g
∘
C
I hope you like this!!!❣️