Calculate the heat developed in 30 minute when 3 a current flows through an electric iron box designed to work under 230 v
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Answer:
1.242*10^6
Explanation:
T=30 min = 1800s
R=V/I
R=230/3
=76.67 ohms
H=I^2RT
H=3^2*76.67*1800
=1242540 Joules
=1.242*10^6 joules
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