Calculate the heat developed when 3A current flows through an electric iron box designed to work under 230V.
Answers
Answered by
133
Answer:
690 joules
Explanation:
Given :
- Current drawn by the electric iron box = 3 Amperes
- Voltage or the potential difference across the iron box = 230 volts
To find :
- Heat developed in 1 second
Heat = v×i×t
Heat = 230×3×1
Heat = 690 joules
The heat generated by the iron box in 1 second is equal to 690 joules
The heat would keep on increasing as the time passes by
Other heat formulas:
- I²rt
Answered by
121
Correct Question :
An electric iron works on 230 V and current of 3 A flows through it for half an hour. How would one calculate the amount of heat energy generated?
Given ,
Voltage , V = 230 V
Current , I = 3 A
Time , t = 1/2 h = 30 min = 1800 s
We know that ,
Heat , Q = I² Rt
⇒ Q = ( IR ) It
⇒ Q = V I t [ From Ω's law V = IR ]
⇒ Q = 230 * 3 * 1800
⇒ Q = 12,42,000 Joules
⇒ Q = 1,242 kW-s
So , the amount of heat energy generated is 1,242 kW-s
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