Question

Calculate the heat developed when 3A current flows through an electric iron box designed to work under 230V.​

Answer 1

Answer:

690 joules

Explanation:

Given :

• Current drawn by the electric iron box = 3 Amperes

• Voltage or the potential difference across the iron box = 230 volts

To find :

• Heat developed in 1 second

Heat = v×i×t

Heat = 230×3×1

Heat = 690 joules

The heat generated by the iron box in 1 second is equal to 690 joules

The heat would keep on increasing as the time passes by

Other heat formulas:

• I²rt

Answer 2

Correct Question :

An electric iron works on 230 V and current of 3 A flows through it for half an hour. How would one calculate the amount of heat energy generated?

Given ,

Voltage , V = 230 V

Current , I = 3 A

Time , t = 1/2 h = 30 min = 1800 s

We know that ,

Heat , Q = I² Rt

⇒ Q = ( IR ) It

⇒ Q = V I t   [ From Ω's law V = IR ]

⇒ Q = 230 * 3 * 1800

⇒ Q = 12,42,000 Joules

⇒ Q = 1,242 kW-s

So , the amount of heat energy generated is 1,242 kW-s