Question

Calculate the heat developed when 3A current flows through an iron box designed to work under 230 V works for 30 seconds. (a) Equation used and unit of heat (b) calculate heat​

Answer 1

Answer:-

• Current=I=3A
• Voltage=V=230V
• Time=t=30s

Resistance:-

Using ohms law

$\\ \sf\longmapsto R=\dfrac{V}{I}$

$\\ \sf\longmapsto R=\dfrac{230}{3}$

$\\ \sf\longmapsto R=76.6\Omega$

Now

using joules law

$\\ \sf\longmapsto Heat=I^2Rt$

$\\ \sf\longmapsto Heat=3^2\times 76.6\times 30$

$\\ \sf\longmapsto Heat=9\times 76.6\times 30$

$\\ \sf\longmapsto Heat=20982J$

Answer 2

Explanation:

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