calculate the heat energy given out by the filament of an electric bulb in 20 sec when the resistance of it is 4 and p.d. acrosss its ends is 12 volt
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H=? V=12 V R=4 ohms t=20
H=voltage square/resistance multiplied to time[to numerator]
H=12*12*20/4
H=2880/4
Therefore,H=720 J
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