Question

calculate the heat energy required to change 12 gr of ice at 10 degrees to water vapour into 100 degrees ​

Answer 1

Answer :

• Heat energy required to change 12 g of ice at 10°C to water vapour into 100°C is 4536 J.

Explanation :

Given :

• Initial temperature of the water, Tᵤ = 10°C
• Final temperature of the water, Tᵥ = 100°C
• Mass of ice, m = 12 g or 0.012 kg

To find :

• Heat energy required to change the temperature, Q = ?

Knowledge required :

Formula for heat energy :

⠀⠀⠀⠀⠀⠀⠀⠀⠀Q = mCₚ∆T⠀

Where,

• Q = Heat energy.
• m = Mass.
• Cₚ = Specific heat energy constant.
• ∆T = Change in temperature.

We know that the Change in temperature is the difference of the final temperature and initial temperature, i.e,

⠀⠀⠀⠀⠀⠀⠀⠀⠀∆T = (Tᵤ - Tᵥ)⠀

So by substituting the value of ∆T in the equation for heat energy, we get :

⠀⠀⠀⠀⠀⠀⠀⠀⠀Q = mCₚ(Tᵤ - Tᵥ)⠀

Solution :

By using the formula for heat energy and substituting the values in it, we get :

⠀⠀=> Q = mCₚ(Tᵤ - Tᵥ)

⠀⠀=> Q = 0.012 × 4200 × (100 - 10) ⠀⠀[∴ Cₚ = 4200 Kg/J °C]

⠀⠀=> Q = 12/1000 × 4200 × 90

⠀⠀=> Q = 12 × 42 × 9

⠀⠀=> Q = 4536

⠀⠀⠀⠀⠀⠀⠀∴ Q = 4536 J

Therefore,

• Heat energy required to change the temperature, Q = 4536 J.