Question

calculate the heat energy required to change 5 grams of ice at minus -5 degree Celsius into water at 20 degree Celsius​

Answer 1

Answer:

Heat required to change the ice into water at given temperature is 512.5 Cal

Explanation:

As we know that heat required to change the phase of ice to water is given as

$Q_1 = mL$

also we know that heat required to increase the temperature of ice is

$Q_2 = ms_{ice}\Delta T$

similarly heat required to change the temperature of water is

$Q_3 = ms_{water}\Delta T$

so we will have

$Q = 5(0.5)(5) + 5(80) + 5(1)(20 - 0)$

$Q = 12.5 + 400 + 100$

$Q = 512.5 Cal$

#Learn

Topic : Calorimetery

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