Question

calculate the heat exchange at constant volume in calorie when 0.1 mol of A reactbfir the reaction given at 300K. 2A(g) --> 3 B(g) +C(l) ; H=900 Cal/mol​

Answer 1

Answer:

baba re

Explanation:

Answer 2

The heat exchange at constant volume in calories when 0.1 mol of A reacts is 90 calories.

• In the given reaction 2 moles of A react to form 3 moles of B and 1 mole of C.
• The energy released per mole of the reactant used is 200 Cal. So, the energy for 2 moles of A = 900 X 2 = 1800 Cal.
• Using the unitary method, the energy released when 0.1 moles of A reacts will be 1800 / 20 = 90 Cal.
• Hence, the heat released when 0.1 moels of A completely react according to the given equation, 90 calories of heat is released.