calculate the heat generated in an iron box, operated at 250V, if 4A current is passed through it for 1 minutes
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Answer:
P = i^2Rt
p= iVt
p=4×250×60
p= 60000 W
p= 60Kw
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Answer:
An electric iron works on 230 V and current of 3 A flows through it for half an hour. How would one calculate the amount of heat energy generated?
Given ,
Voltage , V = 230 V
Current , I = 3 A
Time , t = 1/2 h = 30 min = 1800 s
We know that ,
Heat , Q = I² Rt
⇒ Q = ( IR ) It
⇒ Q = V I t [ From Ω's law V = IR ]
⇒ Q = 230 * 3 * 1800
⇒ Q = 12,42,000 Joules
⇒ Q = 1,242 kW-s
So , the amount of heat energy generated is 1,242 kW-s
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