Question

calculate the heat generated while transferring 96000 C of charge in one hour through a PD of 50 V.

Answer 1

Answer:

Solution:Given Charge, Q = 96000C

Time, t= 1hr = 60 x 60= 3600s

Potential difference, V= 50volts

Now we know that H= VIt

so we have to calculate I first

As I= Q/t

∴ I = 96000/3600 = 80/3 A

Therefore, the heat generated is 4.8 x 106 J.

Answer 2

Answer:

Given charge Q = 96000 coulomb.

time = 1hr = 60 * 60 = 3600s.

Potential difference {V} = 50v

According to formula: H= VIT -(i)

Also I = Q/T

∴I  = 96000/3600 =80/3= Ampere

putting value of I = 80/3 Ampere in (i)

H=50 X 80/3 X 60 X 60 = 4.8 X 10²×³joule

Heat is generated that is 4.8 X 10²×³ joule