Calculate the heat of combustion of ethylene (gas) to form CO2(gas) and H2O (gas) at 298Kand 1 atmospheric pressure. The heats of formation of CO2, H2O and C2H4are –394, -242,+52kJ per mole respectively.C2H4(g) + 3O2(g)--2CO2(g) + 2H2O (g)
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Solution:-
Combustion of C
2
H
4
-
C
2
H
4
(g)
+3O
2
(g)
⟶2CO
2
(g)
+2H
2
O
(l)
For the above reaction-
ΔH=∑ΔH
f
P
−∑ΔH
f
R
ΔH=(2×(−394)+2×(−286))−(52+0)
ΔH=−1360+52=−1308kJ/mol
Hence the enthapy of combustion of C
2
H
4
(g)
is −1308kJ/mol
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